MongDB&SQL语法对照


  • Lv 1

    MongoDB语法:                            MySql语法:
    db.test.find({'name':'foobar'})                      select * from test where name='foobar'
    select * from test where name='foobar'      select *from test
    db.test.find({'ID':10}).count()                      select count(*) from test where ID=10
    db.test.find({'ID':10}).count()                      select count(*) from test where ID=10
    db.test.find().skip(10).limit(20)                   select * from test limit 10,20
    db.test.find({'ID':{$in:[25,35,45]}})             select * from test where ID in (25,35,45)
    db.test.find().sort({'ID':-1})                        select * from test order by IDdesc
    db.test.distinct('name',{'ID':{$lt:20}})         select distinct(name) from testwhere ID<20
    db.test.group({key:{'name':true},cond:{'name':'foo'},reduce:function(obj,prev){prev.msum+=obj.marks;},initial:{msum:0}})                select name,sum(marks) from testgroup by name
    db.test.find('this.ID<20',{name:1})           select name from test whereID<20
    db.test.insert({'name':'foobar','age':25})   insertinto test ('name','age') values('foobar',25)
    db.test.remove({})                                    delete * from test
    db.test.remove({'age':20})                       delete test where age=20
    db.test.remove({'age':{$lt:20}})               delete test where age<20
    db.test.remove({'age':{$lte:20}})             delete test where age<=20
    db.test.remove({'age':{$gt:20}})             delete test where age>20
    db.test.remove({'age':{$gte:20}})           delete test where age>=20
    db.test.remove({'age':{$ne:20}})            delete test where age!=20
    db.test.update({'name':'foobar'},{$set:{'age':36}})                update test set age=36 where name='foobar'
    db.test.update({'name':'foobar'},{$inc:{'age':3}})                  update test set age=age+3 where name='foobar'


  • Lv 1

    實用好文...感謝分享... 收藏


  • 註冊用戶

    感謝分享...收藏


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