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现在项目中需要显示gridfs里存储的文件的文件名（filename），请问，如何得到gridfs里fs.files的属性项？
@Jerry
GridFS 基本上算是一種儲存規範, 實際上還是存在 Document. 存取 fs.files 就是一般查詢, 如
db['fs.files'].find({ "_id": ObjectId("58b8fc487f204922fc638644") })
与 萌阔论坛 的连接断开，我们正在尝试重连，请耐心等待
